3(7t-3)=21(t-2)+33

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Solution for 3(7t-3)=21(t-2)+33 equation: 



3(7t-3)=21(t-2)+33

We move all terms to the left:

3(7t-3)-(21(t-2)+33)=0

We multiply parentheses

21t-(21(t-2)+33)-9=0



We calculate terms in parentheses: -(21(t-2)+33), so:

21(t-2)+33

We multiply parentheses

21t-42+33

We add all the numbers together, and all the variables

21t-9

Back to the equation:

-(21t-9)



We get rid of parentheses

21t-21t+9-9=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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