3(7u+2)=3(2u+7)

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Solution for 3(7u+2)=3(2u+7) equation: 



3(7u+2)=3(2u+7)

We move all terms to the left:

3(7u+2)-(3(2u+7))=0

We multiply parentheses

21u-(3(2u+7))+6=0



We calculate terms in parentheses: -(3(2u+7)), so:

3(2u+7)

We multiply parentheses

6u+21

Back to the equation:

-(6u+21)



We get rid of parentheses

21u-6u-21+6=0

We add all the numbers together, and all the variables

15u-15=0

We move all terms containing u to the left, all other terms to the right

15u=15

u=15/15

u=1

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