3(7u-6)+9u=6(u+2)

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Solution for 3(7u-6)+9u=6(u+2) equation: 



3(7u-6)+9u=6(u+2)

We move all terms to the left:

3(7u-6)+9u-(6(u+2))=0

We add all the numbers together, and all the variables

9u+3(7u-6)-(6(u+2))=0

We multiply parentheses

9u+21u-(6(u+2))-18=0



We calculate terms in parentheses: -(6(u+2)), so:

6(u+2)

We multiply parentheses

6u+12

Back to the equation:

-(6u+12)



We add all the numbers together, and all the variables

30u-(6u+12)-18=0

We get rid of parentheses

30u-6u-12-18=0

We add all the numbers together, and all the variables

24u-30=0

We move all terms containing u to the left, all other terms to the right

24u=30

u=30/24

u=1+1/4

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