3(7v+4)-8v=-2(-v-4)+7v

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Solution for 3(7v+4)-8v=-2(-v-4)+7v equation: 



3(7v+4)-8v=-2(-v-4)+7v

We move all terms to the left:

3(7v+4)-8v-(-2(-v-4)+7v)=0

We add all the numbers together, and all the variables

3(7v+4)-8v-(-2(-1v-4)+7v)=0

We add all the numbers together, and all the variables

-8v+3(7v+4)-(-2(-1v-4)+7v)=0

We multiply parentheses

-8v+21v-(-2(-1v-4)+7v)+12=0



We calculate terms in parentheses: -(-2(-1v-4)+7v), so:

-2(-1v-4)+7v

We add all the numbers together, and all the variables

7v-2(-1v-4)

We multiply parentheses

7v+2v+8

We add all the numbers together, and all the variables

9v+8

Back to the equation:

-(9v+8)



We add all the numbers together, and all the variables

13v-(9v+8)+12=0

We get rid of parentheses

13v-9v-8+12=0

We add all the numbers together, and all the variables

4v+4=0

We move all terms containing v to the left, all other terms to the right

4v=-4

v=-4/4

v=-1

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