3(7v+4)=21v+12

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Solution for 3(7v+4)=21v+12 equation: 



3(7v+4)=21v+12

We move all terms to the left:

3(7v+4)-(21v+12)=0

We multiply parentheses

21v-(21v+12)+12=0

We get rid of parentheses

21v-21v-12+12=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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