3(7x+4)=6(2x-1)-12

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Solution for 3(7x+4)=6(2x-1)-12 equation: 



3(7x+4)=6(2x-1)-12

We move all terms to the left:

3(7x+4)-(6(2x-1)-12)=0

We multiply parentheses

21x-(6(2x-1)-12)+12=0



We calculate terms in parentheses: -(6(2x-1)-12), so:

6(2x-1)-12

We multiply parentheses

12x-6-12

We add all the numbers together, and all the variables

12x-18

Back to the equation:

-(12x-18)



We get rid of parentheses

21x-12x+18+12=0

We add all the numbers together, and all the variables

9x+30=0

We move all terms containing x to the left, all other terms to the right

9x=-30

x=-30/9

x=-3+1/3

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