3(7x+8)+4x=7x-11(2x-5)

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Solution for 3(7x+8)+4x=7x-11(2x-5) equation: 



3(7x+8)+4x=7x-11(2x-5)

We move all terms to the left:

3(7x+8)+4x-(7x-11(2x-5))=0

We add all the numbers together, and all the variables

4x+3(7x+8)-(7x-11(2x-5))=0

We multiply parentheses

4x+21x-(7x-11(2x-5))+24=0



We calculate terms in parentheses: -(7x-11(2x-5)), so:

7x-11(2x-5)

We multiply parentheses

7x-22x+55

We add all the numbers together, and all the variables

-15x+55

Back to the equation:

-(-15x+55)



We add all the numbers together, and all the variables

25x-(-15x+55)+24=0

We get rid of parentheses

25x+15x-55+24=0

We add all the numbers together, and all the variables

40x-31=0

We move all terms containing x to the left, all other terms to the right

40x=31

x=31/40

x=31/40

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