3(7x-37x/72)/(39*7x/13)=89

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Solution for 3(7x-37x/72)/(39*7x/13)=89 equation:


D( x )

(7*39*x)/13 = 0

(7*39*x)/13 = 0

(7*39*x)/13 = 0

21*x = 0 // : 21

x = 0

x in (-oo:0) U (0:+oo)

(3*(7*x-((37*x)/72)))/((7*39*x)/13) = 89 // - 89

(3*(7*x-((37*x)/72)))/((7*39*x)/13)-89 = 0

(3*(7*x+(-37/72)*x))/((7*39*x)/13)-89 = 0

(3*467/72*x)/(21*x)-89 = 0

(3*467/72*x)/(21*x)+(-89*21*x)/(21*x) = 0

3*467/72*x-89*21*x = 0

-44389/24*x = 0

(-44389/24*x)/(21*x) = 0

(-44389/24*x)/(21*x) = 0 // * 21*x

(-44389*x)/24 = 0

-44389/24*x = 0 // : -44389/24

x = 0

x in { 0}

x belongs to the empty set

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