3(7x-4)+3(x+2)=6(x+10)-(x+4)

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Solution for 3(7x-4)+3(x+2)=6(x+10)-(x+4) equation: 



3(7x-4)+3(x+2)=6(x+10)-(x+4)

We move all terms to the left:

3(7x-4)+3(x+2)-(6(x+10)-(x+4))=0

We multiply parentheses

21x+3x-(6(x+10)-(x+4))-12+6=0



We calculate terms in parentheses: -(6(x+10)-(x+4)), so:

6(x+10)-(x+4)

We multiply parentheses

6x-(x+4)+60

We get rid of parentheses

6x-x-4+60

We add all the numbers together, and all the variables

5x+56

Back to the equation:

-(5x+56)



We add all the numbers together, and all the variables

24x-(5x+56)-6=0

We get rid of parentheses

24x-5x-56-6=0

We add all the numbers together, and all the variables

19x-62=0

We move all terms containing x to the left, all other terms to the right

19x=62

x=62/19

x=3+5/19

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