3(7x-4)-(x+8)+14=11x+12

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Solution for 3(7x-4)-(x+8)+14=11x+12 equation: 



3(7x-4)-(x+8)+14=11x+12

We move all terms to the left:

3(7x-4)-(x+8)+14-(11x+12)=0

We multiply parentheses

21x-(x+8)-(11x+12)-12+14=0

We get rid of parentheses

21x-x-11x-8-12-12+14=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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