3(7x-4)=21x+6-18

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Solution for 3(7x-4)=21x+6-18 equation: 



3(7x-4)=21x+6-18

We move all terms to the left:

3(7x-4)-(21x+6-18)=0

We add all the numbers together, and all the variables

3(7x-4)-(21x-12)=0

We multiply parentheses

21x-(21x-12)-12=0

We get rid of parentheses

21x-21x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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