3(7y-4)=-17+6y

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Solution for 3(7y-4)=-17+6y equation: 



3(7y-4)=-17+6y

We move all terms to the left:

3(7y-4)-(-17+6y)=0

We add all the numbers together, and all the variables

3(7y-4)-(6y-17)=0

We multiply parentheses

21y-(6y-17)-12=0

We get rid of parentheses

21y-6y+17-12=0

We add all the numbers together, and all the variables

15y+5=0

We move all terms containing y to the left, all other terms to the right

15y=-5

y=-5/15

y=-1/3

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