3(7z+4)=-23

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Solution for 3(7z+4)=-23 equation: 



3(7z+4)=-23

We move all terms to the left:

3(7z+4)-(-23)=0

We add all the numbers together, and all the variables

3(7z+4)+23=0

We multiply parentheses

21z+12+23=0

We add all the numbers together, and all the variables

21z+35=0

We move all terms containing z to the left, all other terms to the right

21z=-35

z=-35/21

z=-1+2/3

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