3(7z+4)=74

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Solution for 3(7z+4)=74 equation: 



3(7z+4)=74

We move all terms to the left:

3(7z+4)-(74)=0

We multiply parentheses

21z+12-74=0

We add all the numbers together, and all the variables

21z-62=0

We move all terms containing z to the left, all other terms to the right

21z=62

z=62/21

z=2+20/21

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