3(7z+4)=74

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Solution for 3(7z+4)=74 equation:



3(7z+4)=74
We move all terms to the left:
3(7z+4)-(74)=0
We multiply parentheses
21z+12-74=0
We add all the numbers together, and all the variables
21z-62=0
We move all terms containing z to the left, all other terms to the right
21z=62
z=62/21
z=2+20/21

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