3(7z-23)=99

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Solution for 3(7z-23)=99 equation: 



3(7z-23)=99

We move all terms to the left:

3(7z-23)-(99)=0

We multiply parentheses

21z-69-99=0

We add all the numbers together, and all the variables

21z-168=0

We move all terms containing z to the left, all other terms to the right

21z=168

z=168/21

z=8

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