3(7z-23)=99z=

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Solution for 3(7z-23)=99z= equation: 



3(7z-23)=99z=

We move all terms to the left:

3(7z-23)-(99z)=0

We add all the numbers together, and all the variables

-99z+3(7z-23)=0

We multiply parentheses

-99z+21z-69=0

We add all the numbers together, and all the variables

-78z-69=0

We move all terms containing z to the left, all other terms to the right

-78z=69

z=69/-78

z=-23/26

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