3(7z-9)-5=31

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Solution for 3(7z-9)-5=31 equation: 



3(7z-9)-5=31

We move all terms to the left:

3(7z-9)-5-(31)=0

We add all the numbers together, and all the variables

3(7z-9)-36=0

We multiply parentheses

21z-27-36=0

We add all the numbers together, and all the variables

21z-63=0

We move all terms containing z to the left, all other terms to the right

21z=63

z=63/21

z=3

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