3(7z=23)=99

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Solution for 3(7z=23)=99 equation: 



3(7z=23)=99

We move all terms to the left:

3(7z-(23))=0

We multiply parentheses

21z-69=0

We move all terms containing z to the left, all other terms to the right

21z=69

z=69/21

z=3+2/7

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