3(8+2y)=2(3y+12)

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Solution for 3(8+2y)=2(3y+12) equation: 



3(8+2y)=2(3y+12)

We move all terms to the left:

3(8+2y)-(2(3y+12))=0

We add all the numbers together, and all the variables

3(2y+8)-(2(3y+12))=0

We multiply parentheses

6y-(2(3y+12))+24=0



We calculate terms in parentheses: -(2(3y+12)), so:

2(3y+12)

We multiply parentheses

6y+24

Back to the equation:

-(6y+24)



We get rid of parentheses

6y-6y-24+24=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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