3(8-2x)+5=17-2(1-x)

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Solution for 3(8-2x)+5=17-2(1-x) equation: 



3(8-2x)+5=17-2(1-x)

We move all terms to the left:

3(8-2x)+5-(17-2(1-x))=0

We add all the numbers together, and all the variables

3(-2x+8)-(17-2(-1x+1))+5=0

We multiply parentheses

-6x-(17-2(-1x+1))+24+5=0



We calculate terms in parentheses: -(17-2(-1x+1)), so:

17-2(-1x+1)

determiningTheFunctionDomain
-2(-1x+1)+17

We multiply parentheses

2x-2+17

We add all the numbers together, and all the variables

2x+15

Back to the equation:

-(2x+15)



We add all the numbers together, and all the variables

-6x-(2x+15)+29=0

We get rid of parentheses

-6x-2x-15+29=0

We add all the numbers together, and all the variables

-8x+14=0

We move all terms containing x to the left, all other terms to the right

-8x=-14

x=-14/-8

x=1+3/4

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