3(8-2x)=2(7x-19)=

Solution for 3(8-2x)=2(7x-19)= equation:

3(8-2x)=2(7x-19)=

We move all terms to the left:

3(8-2x)-(2(7x-19))=0

We add all the numbers together, and all the variables

3(-2x+8)-(2(7x-19))=0

We multiply parentheses

-6x-(2(7x-19))+24=0


We calculate terms in parentheses: -(2(7x-19)), so:

2(7x-19)

We multiply parentheses

14x-38

Back to the equation:

-(14x-38)


We get rid of parentheses

-6x-14x+38+24=0

We add all the numbers together, and all the variables

-20x+62=0

We move all terms containing x to the left, all other terms to the right

-20x=-62

x=-62/-20

x=3+1/10