3(8-4e)=2(10e+8)

Solution for 3(8-4e)=2(10e+8) equation:

3(8-4e)=2(10e+8)

We move all terms to the left:

3(8-4e)-(2(10e+8))=0

We add all the numbers together, and all the variables

3(-4e+8)-(2(10e+8))=0

We multiply parentheses

-12e-(2(10e+8))+24=0


We calculate terms in parentheses: -(2(10e+8)), so:

2(10e+8)

We multiply parentheses

20e+16

Back to the equation:

-(20e+16)


We get rid of parentheses

-12e-20e-16+24=0

We add all the numbers together, and all the variables

-32e+8=0

We move all terms containing e to the left, all other terms to the right

-32e=-8

e=-8/-32

e=1/4