3(8-b)-32=17b-4(2+5b)

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Solution for 3(8-b)-32=17b-4(2+5b) equation: 



3(8-b)-32=17b-4(2+5b)

We move all terms to the left:

3(8-b)-32-(17b-4(2+5b))=0

We add all the numbers together, and all the variables

3(-1b+8)-(17b-4(5b+2))-32=0

We multiply parentheses

-3b-(17b-4(5b+2))+24-32=0



We calculate terms in parentheses: -(17b-4(5b+2)), so:

17b-4(5b+2)

We multiply parentheses

17b-20b-8

We add all the numbers together, and all the variables

-3b-8

Back to the equation:

-(-3b-8)



We add all the numbers together, and all the variables

-3b-(-3b-8)-8=0

We get rid of parentheses

-3b+3b+8-8=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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