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3(8-y)=6(1/2y-4)
We move all terms to the left:
3(8-y)-(6(1/2y-4))=0
Domain of the equation: 2y-4))!=0We add all the numbers together, and all the variables
y∈R
3(-1y+8)-(6(1/2y-4))=0
We multiply parentheses
-3y-(6(1/2y-4))+24=0
We multiply all the terms by the denominator
-3y*2y+24*2y-4))-(6(1-4))=0
We add all the numbers together, and all the variables
-3y*2y+24*2y-4))-(6(-3))=0
We add all the numbers together, and all the variables
-3y*2y+24*2y=0
Wy multiply elements
-6y^2+48y=0
a = -6; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·(-6)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*-6}=\frac{-96}{-12} =+8 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*-6}=\frac{0}{-12} =0 $
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