3(8f+5)=28-4f

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Solution for 3(8f+5)=28-4f equation: 



3(8f+5)=28-4f

We move all terms to the left:

3(8f+5)-(28-4f)=0

We add all the numbers together, and all the variables

3(8f+5)-(-4f+28)=0

We multiply parentheses

24f-(-4f+28)+15=0

We get rid of parentheses

24f+4f-28+15=0

We add all the numbers together, and all the variables

28f-13=0

We move all terms containing f to the left, all other terms to the right

28f=13

f=13/28

f=13/28

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