3(8t+1)-12=t-(t-8)

Solution for 3(8t+1)-12=t-(t-8) equation:

3(8t+1)-12=t-(t-8)

We move all terms to the left:

3(8t+1)-12-(t-(t-8))=0

We multiply parentheses

24t-(t-(t-8))+3-12=0


We calculate terms in parentheses: -(t-(t-8)), so:

t-(t-8)

We get rid of parentheses

t-t+8

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)


We add all the numbers together, and all the variables

24t-17=0

We move all terms containing t to the left, all other terms to the right

24t=17

t=17/24

t=17/24