3(8t+1)-6=t-(t-2)

Solution for 3(8t+1)-6=t-(t-2) equation:

3(8t+1)-6=t-(t-2)

We move all terms to the left:

3(8t+1)-6-(t-(t-2))=0

We multiply parentheses

24t-(t-(t-2))+3-6=0


We calculate terms in parentheses: -(t-(t-2)), so:

t-(t-2)

We get rid of parentheses

t-t+2

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)


We add all the numbers together, and all the variables

24t-5=0

We move all terms containing t to the left, all other terms to the right

24t=5

t=5/24

t=5/24