3(8x-4)+2x=8x+12+6x

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Solution for 3(8x-4)+2x=8x+12+6x equation:



3(8x-4)+2x=8x+12+6x
We move all terms to the left:
3(8x-4)+2x-(8x+12+6x)=0
We add all the numbers together, and all the variables
3(8x-4)+2x-(14x+12)=0
We add all the numbers together, and all the variables
2x+3(8x-4)-(14x+12)=0
We multiply parentheses
2x+24x-(14x+12)-12=0
We get rid of parentheses
2x+24x-14x-12-12=0
We add all the numbers together, and all the variables
12x-24=0
We move all terms containing x to the left, all other terms to the right
12x=24
x=24/12
x=2

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