3(8x-5)=-2(2x-20)+1

Solution for 3(8x-5)=-2(2x-20)+1 equation:

3(8x-5)=-2(2x-20)+1

We move all terms to the left:

3(8x-5)-(-2(2x-20)+1)=0

We multiply parentheses

24x-(-2(2x-20)+1)-15=0


We calculate terms in parentheses: -(-2(2x-20)+1), so:

-2(2x-20)+1

We multiply parentheses

-4x+40+1

We add all the numbers together, and all the variables

-4x+41

Back to the equation:

-(-4x+41)


We get rid of parentheses

24x+4x-41-15=0

We add all the numbers together, and all the variables

28x-56=0

We move all terms containing x to the left, all other terms to the right

28x=56

x=56/28

x=2