3(9-(2/3y))+2y=27

Solution for 3(9-(2/3y))+2y=27 equation:

3(9-(2/3y))+2y=27

We move all terms to the left:

3(9-(2/3y))+2y-(27)=0


Domain of the equation: 3y))!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

3(9-(+2/3y))+2y-27=0

We add all the numbers together, and all the variables

2y+3(9-(+2/3y))-27=0

We multiply all the terms by the denominator


2y*3y))+3(9-(-27*3y))+2=0

Wy multiply elements

6y^2-81y=0

a = 6; b = -81; c = 0;
Δ = b2-4ac
Δ = -812-4·6·0
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6561}=81$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-81}{2*6}=\frac{0}{12}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+81}{2*6}=\frac{162}{12}
=13+1/2
$