3(9-4)+y=56+4y-8(y+3)

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Solution for 3(9-4)+y=56+4y-8(y+3) equation: 



3(9-4)+y=56+4y-8(y+3)

We move all terms to the left:

3(9-4)+y-(56+4y-8(y+3))=0

We add all the numbers together, and all the variables

y-(56+4y-8(y+3))+35=0



We calculate terms in parentheses: -(56+4y-8(y+3)), so:

56+4y-8(y+3)

determiningTheFunctionDomain
4y-8(y+3)+56

We multiply parentheses

4y-8y-24+56

We add all the numbers together, and all the variables

-4y+32

Back to the equation:

-(-4y+32)



We get rid of parentheses

y+4y-32+35=0

We add all the numbers together, and all the variables

5y+3=0

We move all terms containing y to the left, all other terms to the right

5y=-3

y=-3/5

y=-3/5

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