3(9-4t)=21-6(t+1)

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Solution for 3(9-4t)=21-6(t+1) equation: 



3(9-4t)=21-6(t+1)

We move all terms to the left:

3(9-4t)-(21-6(t+1))=0

We add all the numbers together, and all the variables

3(-4t+9)-(21-6(t+1))=0

We multiply parentheses

-12t-(21-6(t+1))+27=0



We calculate terms in parentheses: -(21-6(t+1)), so:

21-6(t+1)

determiningTheFunctionDomain
-6(t+1)+21

We multiply parentheses

-6t-6+21

We add all the numbers together, and all the variables

-6t+15

Back to the equation:

-(-6t+15)



We get rid of parentheses

-12t+6t-15+27=0

We add all the numbers together, and all the variables

-6t+12=0

We move all terms containing t to the left, all other terms to the right

-6t=-12

t=-12/-6

t=+2

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