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3(9-4x)=2(3x+4)
We move all terms to the left:
3(9-4x)-(2(3x+4))=0
We add all the numbers together, and all the variables
3(-4x+9)-(2(3x+4))=0
We multiply parentheses
-12x-(2(3x+4))+27=0
We calculate terms in parentheses: -(2(3x+4)), so:We get rid of parentheses
2(3x+4)
We multiply parentheses
6x+8
Back to the equation:
-(6x+8)
-12x-6x-8+27=0
We add all the numbers together, and all the variables
-18x+19=0
We move all terms containing x to the left, all other terms to the right
-18x=-19
x=-19/-18
x=1+1/18
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