3(9-c)=2(c+1)

Solution for 3(9-c)=2(c+1) equation:

3(9-c)=2(c+1)

We move all terms to the left:

3(9-c)-(2(c+1))=0

We add all the numbers together, and all the variables

3(-1c+9)-(2(c+1))=0

We multiply parentheses

-3c-(2(c+1))+27=0


We calculate terms in parentheses: -(2(c+1)), so:

2(c+1)

We multiply parentheses

2c+2

Back to the equation:

-(2c+2)


We get rid of parentheses

-3c-2c-2+27=0

We add all the numbers together, and all the variables

-5c+25=0

We move all terms containing c to the left, all other terms to the right

-5c=-25

c=-25/-5

c=+5