3(9-n)n=0

Solution for 3(9-n)n=0 equation:

3(9-n)n=0

We add all the numbers together, and all the variables

3(-1n+9)n=0

We multiply parentheses

-3n^2+27n=0

a = -3; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-3)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-3}=\frac{-54}{-6}
=+9
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-3}=\frac{0}{-6}
=0
$