3(9-x)-(x+2)=5+6(x-5)

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Solution for 3(9-x)-(x+2)=5+6(x-5) equation: 



3(9-x)-(x+2)=5+6(x-5)

We move all terms to the left:

3(9-x)-(x+2)-(5+6(x-5))=0

We add all the numbers together, and all the variables

3(-1x+9)-(x+2)-(5+6(x-5))=0

We multiply parentheses

-3x-(x+2)-(5+6(x-5))+27=0

We get rid of parentheses

-3x-x-(5+6(x-5))-2+27=0



We calculate terms in parentheses: -(5+6(x-5)), so:

5+6(x-5)

determiningTheFunctionDomain
6(x-5)+5

We multiply parentheses

6x-30+5

We add all the numbers together, and all the variables

6x-25

Back to the equation:

-(6x-25)



We add all the numbers together, and all the variables

-4x-(6x-25)+25=0

We get rid of parentheses

-4x-6x+25+25=0

We add all the numbers together, and all the variables

-10x+50=0

We move all terms containing x to the left, all other terms to the right

-10x=-50

x=-50/-10

x=+5

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