3(9-x-4x)+8(3x+4)=11

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Solution for 3(9-x-4x)+8(3x+4)=11 equation: 



3(9-x-4x)+8(3x+4)=11

We move all terms to the left:

3(9-x-4x)+8(3x+4)-(11)=0

We add all the numbers together, and all the variables

3(-5x+9)+8(3x+4)-11=0

We multiply parentheses

-15x+24x+27+32-11=0

We add all the numbers together, and all the variables

9x+48=0

We move all terms containing x to the left, all other terms to the right

9x=-48

x=-48/9

x=-5+1/3

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