3(9-z)/2=z

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Solution for 3(9-z)/2=z equation: 



3(9-z)/2=z

We move all terms to the left:

3(9-z)/2-(z)=0

We add all the numbers together, and all the variables

3(-1z+9)/2-z=0

We add all the numbers together, and all the variables

-1z+3(-1z+9)/2=0

We multiply all the terms by the denominator


-1z*2+3(-1z+9)=0

We multiply parentheses

-1z*2-3z+27=0

Wy multiply elements

-2z-3z+27=0

We add all the numbers together, and all the variables

-5z+27=0

We move all terms containing z to the left, all other terms to the right

-5z=-27

z=-27/-5

z=5+2/5

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