3(96x)-144=72(12x)+84

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Solution for 3(96x)-144=72(12x)+84 equation: 



3(96x)-144=72(12x)+84

We move all terms to the left:

3(96x)-144-(72(12x)+84)=0

We get rid of parentheses

396x-7212x-84-144=0

We add all the numbers together, and all the variables

-6816x-228=0

We move all terms containing x to the left, all other terms to the right

-6816x=228

x=228/-6816

x=-19/568

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