3(9c+5)=27c+1

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Solution for 3(9c+5)=27c+1 equation: 


Simplifying
3(9c + 5) = 27c + 1

Reorder the terms:
3(5 + 9c) = 27c + 1
(5 * 3 + 9c * 3) = 27c + 1
(15 + 27c) = 27c + 1

Reorder the terms:
15 + 27c = 1 + 27c

Add '-27c' to each side of the equation.
15 + 27c + -27c = 1 + 27c + -27c

Combine like terms: 27c + -27c = 0
15 + 0 = 1 + 27c + -27c
15 = 1 + 27c + -27c

Combine like terms: 27c + -27c = 0
15 = 1 + 0
15 = 1

Solving
15 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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