3(9c-4)=2(3c-20)

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Solution for 3(9c-4)=2(3c-20) equation:


Simplifying
3(9c + -4) = 2(3c + -20)

Reorder the terms:
3(-4 + 9c) = 2(3c + -20)
(-4 * 3 + 9c * 3) = 2(3c + -20)
(-12 + 27c) = 2(3c + -20)

Reorder the terms:
-12 + 27c = 2(-20 + 3c)
-12 + 27c = (-20 * 2 + 3c * 2)
-12 + 27c = (-40 + 6c)

Solving
-12 + 27c = -40 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
-12 + 27c + -6c = -40 + 6c + -6c

Combine like terms: 27c + -6c = 21c
-12 + 21c = -40 + 6c + -6c

Combine like terms: 6c + -6c = 0
-12 + 21c = -40 + 0
-12 + 21c = -40

Add '12' to each side of the equation.
-12 + 12 + 21c = -40 + 12

Combine like terms: -12 + 12 = 0
0 + 21c = -40 + 12
21c = -40 + 12

Combine like terms: -40 + 12 = -28
21c = -28

Divide each side by '21'.
c = -1.333333333

Simplifying
c = -1.333333333

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