3(9c-9)=5c+8c+2-1

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Solution for 3(9c-9)=5c+8c+2-1 equation: 



3(9c-9)=5c+8c+2-1

We move all terms to the left:

3(9c-9)-(5c+8c+2-1)=0

We add all the numbers together, and all the variables

3(9c-9)-(13c+1)=0

We multiply parentheses

27c-(13c+1)-27=0

We get rid of parentheses

27c-13c-1-27=0

We add all the numbers together, and all the variables

14c-28=0

We move all terms containing c to the left, all other terms to the right

14c=28

c=28/14

c=2

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