3(9x-1)=2(10x+12)

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Solution for 3(9x-1)=2(10x+12) equation: 



3(9x-1)=2(10x+12)

We move all terms to the left:

3(9x-1)-(2(10x+12))=0

We multiply parentheses

27x-(2(10x+12))-3=0



We calculate terms in parentheses: -(2(10x+12)), so:

2(10x+12)

We multiply parentheses

20x+24

Back to the equation:

-(20x+24)



We get rid of parentheses

27x-20x-24-3=0

We add all the numbers together, and all the variables

7x-27=0

We move all terms containing x to the left, all other terms to the right

7x=27

x=27/7

x=3+6/7

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