3(9x-2)+(x-130)=-6(2x-4)

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Solution for 3(9x-2)+(x-130)=-6(2x-4) equation: 



3(9x-2)+(x-130)=-6(2x-4)

We move all terms to the left:

3(9x-2)+(x-130)-(-6(2x-4))=0

We multiply parentheses

27x+(x-130)-(-6(2x-4))-6=0

We get rid of parentheses

27x+x-(-6(2x-4))-130-6=0



We calculate terms in parentheses: -(-6(2x-4)), so:

-6(2x-4)

We multiply parentheses

-12x+24

Back to the equation:

-(-12x+24)



We add all the numbers together, and all the variables

28x-(-12x+24)-136=0

We get rid of parentheses

28x+12x-24-136=0

We add all the numbers together, and all the variables

40x-160=0

We move all terms containing x to the left, all other terms to the right

40x=160

x=160/40

x=4

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