3(9z-6)=23

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Solution for 3(9z-6)=23 equation: 



3(9z-6)=23

We move all terms to the left:

3(9z-6)-(23)=0

We multiply parentheses

27z-18-23=0

We add all the numbers together, and all the variables

27z-41=0

We move all terms containing z to the left, all other terms to the right

27z=41

z=41/27

z=1+14/27

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