3(B+C)=

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Solution for 3(B+C)= equation:


Simplifying
3(B + C) = 0
(B * 3 + C * 3) = 0
(3B + 3C) = 0

Solving
3B + 3C = 0

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-3C' to each side of the equation.
3B + 3C + -3C = 0 + -3C

Combine like terms: 3C + -3C = 0
3B + 0 = 0 + -3C
3B = 0 + -3C
Remove the zero:
3B = -3C

Divide each side by '3'.
B = -1C

Simplifying
B = -1C

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