3(C-1)+2(3c+1)=-3c+1

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Solution for 3(C-1)+2(3c+1)=-3c+1 equation: 



3(-1)+2(3C+1)=-3C+1

We move all terms to the left:

3(-1)+2(3C+1)-(-3C+1)=0

We add all the numbers together, and all the variables

2(3C+1)-(-3C+1)-3=0

We multiply parentheses

6C-(-3C+1)+2-3=0

We get rid of parentheses

6C+3C-1+2-3=0

We add all the numbers together, and all the variables

9C-2=0

We move all terms containing C to the left, all other terms to the right

9C=2

C=2/9

C=2/9

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