3(C-2)+3=2+C-5

Solution for 3(C-2)+3=2+C-5 equation:

Simplifying
3(C + -2) + 3 = 2 + C + -5

Reorder the terms:
3(-2 + C) + 3 = 2 + C + -5
(-2 * 3 + C * 3) + 3 = 2 + C + -5
(-6 + 3C) + 3 = 2 + C + -5

Reorder the terms:
-6 + 3 + 3C = 2 + C + -5

Combine like terms: -6 + 3 = -3
-3 + 3C = 2 + C + -5

Reorder the terms:
-3 + 3C = 2 + -5 + C

Combine like terms: 2 + -5 = -3
-3 + 3C = -3 + C

Add '3' to each side of the equation.
-3 + 3 + 3C = -3 + 3 + C

Combine like terms: -3 + 3 = 0
0 + 3C = -3 + 3 + C
3C = -3 + 3 + C

Combine like terms: -3 + 3 = 0
3C = 0 + C
3C = C

Solving
3C = C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-1C' to each side of the equation.
3C + -1C = C + -1C

Combine like terms: 3C + -1C = 2C
2C = C + -1C

Combine like terms: C + -1C = 0
2C = 0

Divide each side by '2'.
C = 0

Simplifying
C = 0