3(C-4)=4(C-5)

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Solution for 3(C-4)=4(C-5) equation: 


Simplifying
3(C + -4) = 4(C + -5)

Reorder the terms:
3(-4 + C) = 4(C + -5)
(-4 * 3 + C * 3) = 4(C + -5)
(-12 + 3C) = 4(C + -5)

Reorder the terms:
-12 + 3C = 4(-5 + C)
-12 + 3C = (-5 * 4 + C * 4)
-12 + 3C = (-20 + 4C)

Solving
-12 + 3C = -20 + 4C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-4C' to each side of the equation.
-12 + 3C + -4C = -20 + 4C + -4C

Combine like terms: 3C + -4C = -1C
-12 + -1C = -20 + 4C + -4C

Combine like terms: 4C + -4C = 0
-12 + -1C = -20 + 0
-12 + -1C = -20

Add '12' to each side of the equation.
-12 + 12 + -1C = -20 + 12

Combine like terms: -12 + 12 = 0
0 + -1C = -20 + 12
-1C = -20 + 12

Combine like terms: -20 + 12 = -8
-1C = -8

Divide each side by '-1'.
C = 8

Simplifying
C = 8

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