3(F+4)=2(f+6)

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Solution for 3(F+4)=2(f+6) equation: 



3(+4)=2(F+6)

We move all terms to the left:

3(+4)-(2(F+6))=0

We add all the numbers together, and all the variables

-(2(F+6))+34=0



We calculate terms in parentheses: -(2(F+6)), so:

2(F+6)

We multiply parentheses

2F+12

Back to the equation:

-(2F+12)



We get rid of parentheses

-2F-12+34=0

We add all the numbers together, and all the variables

-2F+22=0

We move all terms containing F to the left, all other terms to the right

-2F=-22

F=-22/-2

F=+11

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